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QNEET-2020-Ph-700: NEET 2020 Physics - Class 12 NEET-2020-Ph-700 Solution: The capacitance of a parallel plate capacitor with air as…

The capacitance of a parallel plate capacitor with air as medium is 6μF6\mu F. With the introduction of a dielectric medium the capacitance become 30μF30\mu F The permittivity of the medium is: (ϵ0=8.85×10−12 C2 N−1 m−2\epsilon_0 = 8.85 \times 10^{-12}\ \text{C}^2\ \text{N}^{-1}\ \text{m}^{-2}) 1.77×10−12 C2 N−1 m−21.77 \times 10^{-12}\ \text{C}^2\ \text{N}^{-1}\ \text{m}^{-2} 0.44×10−10 C2 N−1 m−20.44 \times 10^{-10}\ \text{C}^2\ \text{N}^{-1}\ \text{m}^{-2} 5.00 C2 N−1 m−25.00\ \text{C}^2\ \text{N}^{-1}\ \text{m}^{-2} 0.44×10−13 C2 N−1 m−20.44 \times 10^{-13}\ \text{C}^2\ \text{N}^{-1}\ \text{m}^{-2}

Multiple Choice Options

  • A 1.77×10−12C2N−1m−21.77 \times {10^{ - 12}}{C^2}{N^{ - 1}}{m^{ - 2}} 1.77 _ 1 0 _ 12 C 2 N _ 1 m _ 2
  • B 0.44×10−10C2N−1m−20.44 \times {10^{ - 10}}{C^2}{N^{ - 1}}{m^{ - 2}} 0.44 _ 1 0 _ 10 C 2 N _ 1 m _ 2
  • C 5.00C2N−1m−25.00{C^2}{N^{ - 1}}{m^{ - 2}} 5.00 C 2 N _ 1 m _ 2
  • D 0.44×10−13C2N−1m−20.44 \times {10^{ - 13}}{C^2}{N^{ - 1}}{m^{ - 2}} 0.44 _ 1 0 _ 13 C 2 N _ 1 m _ 2

Step-by-Step Verified Solution

The capacitance increases with dielectric constant K C = K C 0 (or) K = C C 0 = 30 6 = 5 _ = K _ 0 = 5 _ 8.85 _ 10 _ 12 = 0.44 _ 10 _ 10

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