Verified Solution • 2025–26 Session moderate

QNEET-2020-Ch-682: NEET 2020 Chemistry - Class 11 NEET-2020-Ch-682 Solution: Find out the solubility of \(Ni(OH)_2\) in 0.1 M NaOH. Given…

Find out the solubility of Ni(OH)2Ni(OH)_2 in 0.1 M NaOH. Given that the ionic product of Ni(OH)2Ni(OH)_2 is 2×10−152 \times 10^{-15}. 2×10−8 M2 \times 10^{-8}\ \text{M} 1×10−13 M1 \times 10^{-13}\ \text{M} 1×108 M1 \times 10^8\ \text{M} 2×10−13 M2 \times 10^{-13}\ \text{M}

Multiple Choice Options

  • A 2 ×\times _ 10 -8 M
  • B 1 ×\times _ 10 -13 M
  • C 1 ×\times _ 10 8 M
  • D 2 ×\times _ 10 -13 M

Step-by-Step Verified Solution

Total [OH - ] = 2s + 0.1 _ 0.1 Ionic product = [Ni 2+ ][OH - ] 2 _ 2 _ 10 -15 = s(0.1) 2 _ s = 2 _ 10 -13

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