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QNEET-2019-Ph-825: NEET 2019 Physics - Class 12 NEET-2019-Ph-825 Solution: An electron is accelerated through a potential difference of…

An electron is accelerated through a potential difference of 10000 V. Its de Broglie wavelength is (nearly): (me=9×10−31 kgm_e = 9 \times 10^{-31}\ \text{kg}) 12.2×10−12 m12.2 \times 10^{-12}\ \text{m} 12.2×10−13 m12.2 \times 10^{-13}\ \text{m} 12.2×10−14 m12.2 \times 10^{-14}\ \text{m} 12.2 nm

Multiple Choice Options

  • A 12.2 _ 10 �12 m
  • B 12.2 _ 10 �13 m
  • C 12.2 _ 10 �14 m
  • D 12.2 nm

Step-by-Step Verified Solution

Expression for an electron accelerated through a potential V is given as _ = 12.27 V A o = 12.27 _ 10 _ 10 10000 = 12.2 _ 10 �12 m

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