Verified Solution • 2025–26 Session moderate

QNEET-2019-Ph-813: NEET 2019 Physics - Class 11 NEET-2019-Ph-813 Solution: The radius of circle the period of revolution initial position…

The radius of circle the period of revolution initial position and sense of revolution are indicated is the figure. y-projection of the radius vector of rotating particle P is: y(t)=4sin⁡(πt2)y(t) = 4\sin(\frac{\pi t}{2}) where y in m y(t)=3cos⁡(3πt2)y(t) = 3\cos(\frac{3\pi t}{2}) where y in m y(t)=3cos⁡(πt2)y(t) = 3\cos(\frac{\pi t}{2}) where y in m y(t)=−3cos⁡2πty(t) = -3\cos2\pi t where y in m

Multiple Choice Options

  • A y(t) = 4sin (πt2)\left( {{{\pi t} \over 2}} \right) ( 2 � t _ ) , where y in m
  • B y(t) = 3cos (3πt2)\left( {{{3\pi t} \over 2}} \right) ( 2 3 � t _ ) , where y in m
  • C y(t) = 3cos (πt2)\left( {{{\pi t} \over 2}} \right) ( 2 � t _ ) , where y in m
  • D y(t) = -3cos2 π\pi � t, where y in m

Step-by-Step Verified Solution

Angular velocity, ( _ ) = 2 � T = 2 � 4 = � 2 rad/s Since, at t = 0, displacement (y) is maximum, so equation will be cosine function. y = a cos _ t _ y = 3 cos ( � t 2 )

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