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QNEET-2019-Ph-802: NEET 2019 Physics - Class 11 NEET-2019-Ph-802 Solution: A soap bubble having radius of 1 mm is blown from a detergent…

A soap bubble having radius of 1 mm is blown from a detergent solution having a surface tension of 2.5×10−2 N/m2.5 \times 10^{-2}\ \text{N/m}. The pressure inside the bubble equals at a point Z0Z_0 below the free surface of water in a container. Taking g = 10 m/s2m/s^2 density of water = 103 kg/m310^3\ \text{kg/m}^3 the value of Z0Z_0 is: 1 cm 10 cm 100 cm 0.5 cm

Multiple Choice Options

  • A 1 cm
  • B 10 cm
  • C 100 cm
  • D 0.5 cm

Step-by-Step Verified Solution

P = P 0 + _ gZ 0 .........(i) Also, P = P 0 + 4 T R .....(ii) From (i) and (ii), _ gZ 0 = 4 T R _ Z 0 = 4 T _ g R = 4 _ 2.5 _ 10 _ 2 10 3 _ 10 _ 10 _ 3 = 10 -2 m = 1 cm

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