Verified Solution • 2025–26 Session moderate

QNEET-2019-Ph-794: NEET 2019 Physics - Class 11 NEET-2019-Ph-794 Solution: When a block of mass M is suspended by a long wire of length L…

When a block of mass M is suspended by a long wire of length L the length of the wire becomes (L + l). The elastic potential energy stored in the extended wire is: Mgl MgLMgL 12Mgl\frac{1}{2}Mgl 12MgL\frac{1}{2}MgL

Multiple Choice Options

  • A Mgl
  • B mgL
  • C 12{1 \over 2} 2 1 _ Mgl
  • D 12{1 \over 2} 2 1 _ MgL

Step-by-Step Verified Solution

Elastic potential energy U = 1 2 (work done due to gravity) = 1 2 Mgl

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