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QNEET-2019-Ph-790: NEET 2019 Physics - Class 12 NEET-2019-Ph-790 Solution: A parallel plate capacitor of capacitance \(20 F\) is being…

A parallel plate capacitor of capacitance 20μF20\mu F is being charged by a voltage source whose potential is changing at the rate of 3 V/s. The conduction current through the connecting wires and the displacement current through the plates of the capacitor would be respectively: zero zero zero 60μA60\mu A 60μA60\mu A 60μA60\mu A 60μA60\mu A zero

Multiple Choice Options

  • A zero, zero
  • B zero, 60 μ\mu _ A
  • C 60 μ\mu _ A, 60 μ\mu _ A
  • D 60 μ\mu _ A, zero

Step-by-Step Verified Solution

As, q = CV Differentiating above equation w.r.t. t, we get d q d t = C d V d t _ i c = C d V d t [As i = d q d t ] = 20 _ 10 -6 _ 3 = 60 _ 10 -6 A = 60 _ A Also, conduction current in wires is equal to displacement current between the plates of capacitor. _ i d = i c = 60 _ A

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