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QNEET-2019-Ph-789: NEET 2019 Physics - Class 11 NEET-2019-Ph-789 Solution: A force F = 20 + 10y acts on a particle in y-direction where F…
A force F = 20 + 10y acts on a particle in y-direction where F is in newton and y in meter. Work done by this force to move the particle from y = 0 to y = 1 m is: 5 J 25 J 20 J 30 J
Multiple Choice Options
- A 5 J
- B 25 J
- C 20 J
- D 30 J
Step-by-Step Verified Solution
Work done under the given variable force is :
W = � y 1 y 1 F d y
Here, y 1 = 0, y 2 = 1 m
_ W = � 0 1 ( 20 + 10 y ) d y
= [ 20 y + 10 y 2 2 ] 0 1 = 25 J