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QNEET-2019-Ph-786: NEET 2019 Physics - Class 11 NEET-2019-Ph-786 Solution: A small hole of area of cross-section 2 \(mm^2\) present near…

A small hole of area of cross-section 2

mm^2

present near the bottom of a fully filled open tank of height 2 m. Taking g = 10

m/s^2

the rate of flow of water through the open hole would be nearly:

8.9 \times 10^{-6}\ \text{m}^3/\text{s}

2.23 \times 10^{-6}\ \text{m}^3/\text{s}

6.4 \times 10^{-6}\ \text{m}^3/\text{s}

12.6 \times 10^{-6}\ \text{m}^3/\text{s}

Step-by-Step Verified Solution

volume flow rate = Av = A 2 g h = 2 _ 10 -6 _ 2 _ 10 _ 2 = 2 _ 2 _ 3.14 _ 10 -6 m 3 /s = 12.56 _ 10 -6 m 3 /s = 12.6 _ 10 -6 m 3 /s