Verified Solution • 2025–26 Session moderate

QNEET-2019-Ch-776: NEET 2019 Chemistry - Class 11 NEET-2019-Ch-776 Solution: pH of a saturated solution of \(Ca(OH)_2\) is 9. The solubility …

pH of a saturated solution of Ca(OH)2Ca(OH)_2 is 9. The solubility product (KspK_{sp}) of Ca(OH)2Ca(OH)_2 is: 0.125×10−150.125 \times 10^{-15} 0.5×10−100.5 \times 10^{-10} 0.5×10−150.5 \times 10^{-15} 0.25×10−100.25 \times 10^{-10}

Multiple Choice Options

  • A 0.125 _ 10 �15
  • B 0.5 _ 10 �10
  • C 0.5 _ 10 �15
  • D 0.25 _ 10 �10

Step-by-Step Verified Solution

Ca(OH) 2 | _ | Ca +2 (aq) | + | 2OH - (aq) S | 2S pH = 9 ; pOH = 5 ; [OH � ] = 10 �5 = 2S _ S = 10 _ 5 2 K sp = [Ca +2 ] [OH � ] 2 _ K sp = S _ (2S) 2 _ K sp = 4S 3 _ K sp = 4 _ ( 10 _ 5 2 ) 3 = 0.5 _ 10 �15

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