Verified Solution • 2025–26 Session moderate

QNEET-2019-Ch-768: NEET 2019 Chemistry - Class 12 NEET-2019-Ch-768 Solution: For the chemical reaction \(N_2(g) + 3H_2(g) 2NH_3(g)\) the…

For the chemical reaction N2(g)+3H2(g)⇌2NH3(g)N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g) the correct option is: −d[N2]dt=2d[NH3]dt-\frac{d[N_2]}{dt} = 2\frac{d[NH_3]}{dt} −d[N2]dt=12d[NH3]dt-\frac{d[N_2]}{dt} = \frac{1}{2}\frac{d[NH_3]}{dt} 3d[H2]dt=2d[NH3]dt3\frac{d[H_2]}{dt} = 2\frac{d[NH_3]}{dt} −13d[H2]dt=−12d[NH3]dt-\frac{1}{3}\frac{d[H_2]}{dt} = -\frac{1}{2}\frac{d[NH_3]}{dt}

Multiple Choice Options

  • A −d[N2]dt=2d[NH3]dt- {{d\left[ {{N_2}} \right]} \over {dt}} = 2{{d\left[ {N{H_3}} \right]} \over {dt}} _ d t d [ N 2 _ ] _ = 2 d t d [ N H 3 _ ] _
  • B −d[N2]dt=12d[NH3]dt- {{d\left[ {{N_2}} \right]} \over {dt}} = {1 \over 2}{{d\left[ {N{H_3}} \right]} \over {dt}} _ d t d [ N 2 _ ] _ = 2 1 _ d t d [ N H 3 _ ] _
  • C 3d[H2]dt=2d[NH3]dt3{{d\left[ {{H_2}} \right]} \over {dt}} = 2{{d\left[ {N{H_3}} \right]} \over {dt}} 3 d t d [ H 2 _ ] _ = 2 d t d [ N H 3 _ ] _
  • D −13d[H2]dt=−12d[NH3]dt- {1 \over 3}{{d\left[ {{H_2}} \right]} \over {dt}} = -{1 \over 2}{{d\left[ {N{H_3}} \right]} \over {dt}} _ 3 1 _ d t d [ H 2 _ ] _ = _ 2 1 _ d t d [ N H 3 _ ] _

Step-by-Step Verified Solution

N 2 (g) + 3H 2 (g) _ 2NH 3 (g Rate of the reaction can be written as : _ d [ N 2 ] d t = _ 1 3 d [ H 2 ] d t = + 1 2 d [ N H 3 ] d t

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