Verified Solution • 2025–26 Session moderate

QNEET-2018-Ph-918: NEET 2018 Physics - Class 11 NEET-2018-Ph-918 Solution: A body initially at rest and sliding along a frictionless track …

A body initially at rest and sliding along a frictionless track from a height h (as shown in the figure) just completes a vertical circle of diameter AB = D. The height h is equal to D 3D/2 7D/5 5D/4

Multiple Choice Options

  • A D
  • B 32D{3 \over 2}D 2 3 _ D
  • C 75D{7 \over 5}D 5 7 _ D
  • D 54D{5 \over 4}D 4 5 _ D

Step-by-Step Verified Solution

Since from the given figure, in order to complete the vertical circle, velocity at the bottom of vertical circle should be 5 g R . As body is at rest initially, i.e., speed = 0. At point A, speed = v. As track is frictionless, so total mechanical energy will remain constant. _ 0 + mgh = 1 2 m v 2 + 0 _ h = v 2 2 g For completing the vertical circle, v � 5 g R _ h = 5 g R 2 g = 5 2 R = 5 4 D

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