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QNEET-2018-Ph-914: NEET 2018 Physics - Class 12 NEET-2018-Ph-914 Solution: A carbon resistor of \((47 4.7)\ {k} \) is to be marked with…
A carbon resistor of is to be marked with rings of different colours for its identification. The colour code sequence will be Violet - Yellow - Orange - Silver Yellow - Violet - Orange - Silver Yellow - Green - Violet - Gold Green - Orange - Violet - Gold
Multiple Choice Options
- A Violet � Yellow � Orange � Silver
- B Yellow � Violet � Orange � Silver
- C Yellow � Green � Violet � Gold
- D Green � Orange � Violet � Gold
Step-by-Step Verified Solution
Colour code for carbon resistor
0 - Black
1 - Brown
2 - Red
3 - Orange
4 - Yellow
5 - Green
6 - Blue
7 - Violet
8 - Grey
9 - White
Tolerance :
� 5% Gold
� 10% Silver
� 20% No colour
(47 � 4.7) k � = 47 _ 10 3 � 10% �
Which shows the colour code Yellow � Violet �
Orange � Silver.