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QNEET-2018-Ph-910: NEET 2018 Physics - Class 11 NEET-2018-Ph-910 Solution: A student measured the diameter of a small steel ball using a…
A student measured the diameter of a small steel ball using a screw gauge of least count 0.001 cm. The main scale reading is 5 mm and zero of circular scale division coincides with 25 divisions above the reference level. If screw gauge has a zero error of -0.004 cm the correct diameter of the ball is 0.521 cm 0.525 cm 0.053 cm 0.529 cm
Multiple Choice Options
- A 0.521 cm
- B 0.525 cm
- C 0.053 cm
- D 0.529 cm
Step-by-Step Verified Solution
Diameter of the ball
= MSR + CSR _ (Least count) � Zero error
= 5 mm + 25 _ 0.001 cm � (�0.004) cm
= 0.5 cm + 25 _ 0.001 cm � (�0.004) cm = 0.529 cm.