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QNEET-2018-Ph-906: NEET 2018 Physics - Class 12 NEET-2018-Ph-906 Solution: A set of n equal resistors of value R each are connected in…
A set of n equal resistors of value R each are connected in series to a battery of emf E and internal resistance R. The current drawn is I. Now the n resistors are connected in parallel to the same battery. Then the current drawn from battery becomes 10I. The value of n is 10 11 20 9
Multiple Choice Options
- A 10
- B 11
- C 20
- D 9
Step-by-Step Verified Solution
n series grouping equivalent resistance
R series = nR
In parallel grouping equivalent resistance
R parallel = R n
Current drawn from a battery when n
resistors are connected in series is
I = E n R + R ......(i)
Current drawn from same battery when n resistors
are connected in parallel is
10I = E R n + R ......(ii)
On dividing eqn. (ii) by (i),
10 = ( n + 1 ) R ( 1 n + 1 ) R
Solving we get, n = 10