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QNEET-2018-Ph-898: NEET 2018 Physics - Class 11 NEET-2018-Ph-898 Solution: The efficiency of an ideal heat engine working between the…
The efficiency of an ideal heat engine working between the freezing point and boiling point of water is 26.8% 20% 6.25% 12.5%
Multiple Choice Options
- A 26.80%
- B 20%
- C 6.25%
- D 12.50%
Step-by-Step Verified Solution
Efficiency of ideal heat engine,
_ = ( 1 _ T 2 T 1 )
Freezing point of water = 0 o C = 273 K
Boiling point of water = 100 o C = (100 + 273) K
= 373 K
_ Sink temperature, T 2
= 0 o C = 0 + 273 = 273 K
_ Source temperature, T 1
= 100 o C = 100 + 273 = 373 K
Percentage efficiency, % _ = ( 1 _ T 2 T 1 ) _ 100
= ( 1 _ 273 373 ) _ 100
= ( 100 373 ) _ 100 = 26.8%