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QNEET-2018-Ph-888: NEET 2018 Physics - Class 11 NEET-2018-Ph-888 Solution: A moving block having mass m collides with another stationary…
A moving block having mass m collides with another stationary block having mass 4m. The lighter block comes to rest after collision. When the initial velocity of the lighter block is v then the value of coefficient of restitution (e) will be 0.5 0.25 0.8 0.4
Multiple Choice Options
- A 0.5
- B 0.25
- C 0.8
- D 0.4
Step-by-Step Verified Solution
From the law of conservation of linear
momentum,
momentum before collision = momentum after
collision, so
mv + 4m _ 0 = m _ 0 + 4mv_
mv = 4mv_ or v = 4v_
Coefficient of restitution,
e = v _ v = v 4 v = 0.25