Verified Solution • 2025–26 Session moderate

QNEET-2018-Ph-887: NEET 2018 Physics - Class 11 NEET-2018-Ph-887 Solution: A pendulum is hung from the roof of a sufficiently high…

A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20 m s−220\ \text{m s}^{-2} at a distance of 5 m from the mean position. The time period of oscillation is 2π s2\pi\ \text{s} π s\pi\ \text{s} 2 s 1 s

Multiple Choice Options

  • A 2 π\pi � s
  • B π\pi � s
  • C 2 s
  • D 1 s

Step-by-Step Verified Solution

Given, acceleration, a = 20 m/s 2 , and displacement, y = 5m Magnitude of acceleration of a particle moving in a SHM is, |a| = _ 2 y; where y is amplitude. _ 20 = _ 2 (5) _ _ = 2 rad/s Time period of pendulum, T = 2 � _ = 2 � 2 = � s

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