Verified Solution • 2025–26 Session moderate

QNEET-2018-Ph-885: NEET 2018 Physics - Class 11 NEET-2018-Ph-885 Solution: The power radiated by a black body is P and it radiates maximum …

The power radiated by a black body is P and it radiates maximum energy at wavelength λ0\lambda_0. If the temperature of the black body is now changed so that it radiates maximum energy at wavelength 34λ0\frac{3}{4}\lambda_0 the power radiated by it becomes nP. The value of n is 4/3 3/4 81/256 256/81

Multiple Choice Options

  • A 34{3 \over 4} 4 3 _
  • B 43{4 \over 3} 3 4 _
  • C 25681{{256} \over {81}} 81 256 _
  • D 81256{{81} \over {256}} 256 81 _

Step-by-Step Verified Solution

From Wien's law, _ max T = constant _ _ max 1 T 1 = _ max 2 T 2 _ _ 0 T 1 = 3 _ 0 4 T 2 _ T 2 T 1 = 4 3 According to Stefan-Boltzmann law, energy emitted unit time by a black body is Ae _ T 4 , _ P _ T 4 So P 2 P 1 = ( T 2 T 1 ) 4 = ( 4 3 ) 4 Here, P 2 = nP and P 1 = P So, n P P = n = ( T 2 T 1 ) 4 = ( 4 3 ) 4 = 256 81

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