QNEET-2018-Ch-867: NEET 2018 Chemistry - Class 11 NEET-2018-Ch-867 Solution: Consider the following species: \(CN^+ CN^- NO\) and CN. Which…

Molecular orbital configuration of NO (15 electrons) is = _ 1 s 2 _ 1 s 2 _ _ 2 s 2 _ 2 s 2 _ _ 2 p z 2 � 2 p x 2 = � 2 p y 2 � 2 p x 1 _ = � 2 p y o _ _ N b = 10 N a = 5 _ BO = 1 2 [ 10 _ 5 ] = 2.5 Moleculer orbital configuration of CN � (14 electrons) is = _ 1 s 2 _ 1 s 2 _ _ 2 s 2 _ 2 s 2 _ � 2 p x 2 = � 2 p y 2 _ 2 p z 2 _ N b = 10 N a = 4 _ BO = 1 2 [ 10 _ 4 ] = 3 Moleculer orbital configuration of CN (13 electrons) is = _ 1 s 2 _ 1 s 2 _ _ 2 s 2 _ 2 s 2 _ � 2 p x 2 = � 2 p y 2 _ 2 p z 1 _ N b = 9 N a = 4 _ BO = 1 2 [ 9 _ 4 ] = 2.5 Moleculer orbital configuration of CN + (12 electrons) is = _ 1 s 2 _ 1 s 2 _ _ 2 s 2 _ 2 s 2 _ � 2 p x 2 = � 2 p y 2 _ N b = 8 N a = 4 _ BO = 1 2 [ 8 _ 4 ] = 2 Hence, CN � has highest bond order.