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QNEET-2018-Ch-852: NEET 2018 Chemistry - Class 11 NEET-2018-Ch-852 Solution: A mixture of 2.3 g formic acid and 4.5 g oxalic acid is treated …
A mixture of 2.3 g formic acid and 4.5 g oxalic acid is treated with conc. . The evolved gaseous mixture is passed through KOH pellets. Weight (in g) of the remaining product at STP will be 1.4 3.0 2.8 4.4
Multiple Choice Options
- A 1.4
- B 3
- C 2.8
- D 4.4
Step-by-Step Verified Solution
HCOOH | _ H 2 S O 4 | H 2 O | + | CO
Initial | 2.3 46 = 1 20 | 0 | 0
Final | 0 | 1 20 | 1 20
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H 2 C 2 O 4 | _ H 2 S O 4 | H 2 O | + | CO | + | CO 2
Initial | 4.5 90 = 1 20 | 0 | 0 | 0
Final | 0 | 1 20 | 1 20 | 1 20
KOH will absorb CO 2 and conc. H 2 SO 4 will absorb obtain water so in final solution only CO left.
Moles of CO formed from both reactions,
= 1 20 + 1 20 = 1 10
_ Mass of CO = moles _ molar mass = 1 10 _ 28 = 2.8 g