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QNEET-2018-Ch-850: NEET 2018 Chemistry - Class 11 NEET-2018-Ch-850 Solution: In which case is number of molecules of water maximum? 18 mL of …

In which case is number of molecules of water maximum? 18 mL of water 0.18 g of water 0.00224 L of water vapours at 1 atm and 273 K 10−310^{-3} mol of water

Multiple Choice Options

  • A 18 mL of water
  • B 0.18 g of water
  • C 0.00224 L of water vapours at 1 atm and 273 K
  • D 10 �3 mol of water

Step-by-Step Verified Solution

(a) 18 mL water : Since, density of H 2 O = 1 g/mL Mass of water = V _ d = 18 _ 1 = 18 g No. of molecules of H 2 O = 18 18 _ N A = 1 _ N A (b) 0.18 g of water : No. of molecules of H 2 O = 0.18 18 _ N A = 0.01 _ N A (c) Volume of H 2 O(g) STP = 0.00224 L No. of molecules of H 2 O = V 22.4 _ N A = 0.00224 22.4 _ N A = 0.0001 _ N A (d) No of Molecules of water = mole _ N A = 10 �3 N A

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