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QNEET-2018-Ch-836: NEET 2018 Chemistry - Class 11 NEET-2018-Ch-836 Solution: The bond dissociation energies of \(X_2\) \(Y_2\) and XY are in …

The bond dissociation energies of X2X_2 Y2Y_2 and XY are in the ratio of 1:0.5:1. ΔH\Delta H for the formation of XY is -200 kJ mol−1mol^{-1}. The bond dissociation energy of X2X_2 will be 800 kJ mol−1mol^{-1} 200 kJ mol−1mol^{-1} 400 kJ mol−1mol^{-1} 100 kJ mol−1mol^{-1}

Multiple Choice Options

  • A 800 kJ mol �1
  • B 200 kJ mol �1
  • C 400 kJ mol �1
  • D 100 kJ mol �1

Step-by-Step Verified Solution

Let bond dissociation energies of X 2 , Y 2 and XY are x kJ mol �1 , 0.5x kJ mol �1 and x kJ mol �1 respectively. 1 2 X 2 + 1 2 Y 2 _ XY; _ H = -200 kJ mol -1 _ H = _(B.E) Reactant - _(B.E) Product _ -200 = [ 1 2 _ x + 1 2 _ 0.5 x ] - [ 1 _ x ] On solving, x = 800 kJ mol �1

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