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QNEET-2017-Ph-994: NEET 2017 Physics - Class 11 NEET-2017-Ph-994 Solution: One end of string of length l is connected to a particle of…

One end of string of length l is connected to a particle of mass 'm' and the other end is connected to a small peg on a smooth horizontal table. If the particle moves in circle with speed 'v' the net force on the particle (directed towards centre) will be (T represents the tension in the string)

T+\frac{mv^2}{l}

T-\frac{mv^2}{l}

zero T

Multiple Choice Options

A $T + {{m{v^2}} \over l}$ T + l m v 2 _
B $T - {{m{v^2}} \over l}$ T _ l m v 2 _
C zero
D $T$ T

Step-by-Step Verified Solution

Centripetal force ( m v 2 l ) is provided by tension so net force on the particle will be equal to tension T.

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