Verified Solution • 2025–26 Session moderate

QNEET-2017-Ph-992: NEET 2017 Physics - Class 12 NEET-2017-Ph-992 Solution: An arrangement of three parallel straight wires placed…

An arrangement of three parallel straight wires placed perpendicular to plane of paper carrying same current I along the same direction as shown in fogure. Magnitude of force per unit length on the middle wire B is given by μ0I22πd\frac{\mu_0 I^2}{2\pi d} 2μ0I2πd\frac{2\mu_0 I^2}{\pi d} 2μ0I2πd\frac{\sqrt{2}\mu_0 I^2}{\pi d} μ0I22πd\frac{\mu_0 I^2}{\sqrt{2}\pi d}

Multiple Choice Options

  • A 2μ0I2πd{{2{\mu _0}{I^2}} \over {\pi d}} � d 2 _ 0 _ I 2 _
  • B 2μ0I2πd{{\sqrt 2 {\mu _0}{I^2}} \over {\pi d}} � d 2 _ _ 0 _ I 2 _
  • C μ0I22πd{{{\mu _0}{I^2}} \over {\sqrt 2 \pi d}} 2 _ � d _ 0 _ I 2 _
  • D μ0I22πd{{{\mu _0}{I^2}} \over {2\pi d}} 2 � d _ 0 _ I 2 _

Step-by-Step Verified Solution

Since same current flowing through both the wires i i = i 2 = i So F 1 = _ 0 i 2 2 � d = F 2 _ Magnitude of force per unit length on the middle wire 'B' F net = F 1 2 + F 2 2 = _ 0 i 2 2 � d

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