Verified Solution • 2025–26 Session moderate

QNEET-2017-Ph-964: NEET 2017 Physics - Class 12 NEET-2017-Ph-964 Solution: Suppose the charge of a proton and an electron differ slightly. …

Suppose the charge of a proton and an electron differ slightly. One of them is −e-e the other is (e+Δe)(e + \Delta e). If the net of electrostatic force and gravitational force between two hydrogen atoms placed at a distance d (much greater than atomic size) apart is zero then Δe\Delta e is of the order of [Given: mass of hydrogen mh=1.67×10−27 kgm_h = 1.67 \times 10^{-27}\ \text{kg}] 10−23 C10^{-23}\ \text{C} 10−37 C10^{-37}\ \text{C} 10−47 C10^{-47}\ \text{C} 10−20 C10^{-20}\ \text{C}

Multiple Choice Options

  • A 10 −- _ 23 C
  • B 10 −- _ 37 C
  • C 10 −- _ 47 C
  • D 10 −- _ 20 C

Step-by-Step Verified Solution

According to question, the net electrostatic force (F E ) = gravitational force (F G ) F E = F G _ 1 4 � _ 0 _ e 2 d 2 = G m 2 d 2 _ _ e = m G K ( 1 4 � _ 0 = k = 9 _ 10 9 ) = 1.67 _ 10 _ 27 6.67 _ 10 _ 11 9 _ 10 9 _ e � 1.436 _ 10 _ 37 C

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