Verified Solution • 2025–26 Session moderate

QNEET-2017-Ph-1003: NEET 2017 Physics - Class 12 NEET-2017-Ph-1003 Solution: The photoelectric threshold wavelength of silver is \(3250…

The photoelectric threshold wavelength of silver is 3250×10−10 m3250 \times 10^{-10}\ \text{m}. The velocity of the electron ejected from a silver surface by ultraviolet light of wavelength 2536×10−10 m2536 \times 10^{-10}\ \text{m} is {Given h=4.14×10−15 eV sh = 4.14 \times 10^{-15}\ \text{eV s} and c=3×108 m s−1c = 3 \times 10^8\ \text{m s}^{-1}} ≈0.6×106 m s−1\approx 0.6 \times 10^6\ \text{m s}^{-1} ≈61×103 m s−1\approx 61 \times 10^3\ \text{m s}^{-1} ≈0.3×106 m s−1\approx 0.3 \times 10^6\ \text{m s}^{-1} ≈6×105 m s−1\approx 6 \times 10^5\ \text{m s}^{-1}

Multiple Choice Options

  • A ≈\approx � 0.6 ×\times _ 10 6 m s −- _ 1
  • B ≈\approx � 61 ×\times _ 10 3 m s −- _ 1
  • C ≈\approx � 0.3 ×\times _ 10 6 m s −- _ 1
  • D ≈\approx � 6 ×\times _ 10 5 m s −- _ 1

Step-by-Step Verified Solution

Minimum energy, E 0 = 12375 3250 eV _ E 0 = 3.81 eV Ultraviolet wavelength, _ = 2536 A o _ Imparted energy, E = 12375 2536 = 4.88 eV Now, max kinetic energy, 1 2 m v 2 = E - E 0 _ v = 2 _ 1.07 _ 1.6 _ 10 _ 19 9.1 _ 10 _ 31 _ v = 0.61 _ 10 6 m/s = 6.0 _ 10 5 m/s

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