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QNEET-2017-Ph-1000: NEET 2017 Physics - Class 12 NEET-2017-Ph-1000 Solution: A capacitor is charged by a battery. The battery is removed and …
A capacitor is charged by a battery. The battery is removed and another identical unchanged capacitor is connected in parallel. The total electrostatic energy of resulting system decreases by a factor of 2 remains the same increases by a factor of 2 increases by a factor of 4
Multiple Choice Options
- A decreases by a factor of 2
- B remains the same
- C increases by a factor of 2
- D increases by a factor of 4
Step-by-Step Verified Solution
When the capacitor is charged by a battery of potential V, then energy stored in the capacitor,
U i = 1 2 C V 2 ...(i)
When the battery is removed and another identical uncharged capacitor is connected in parallel
Common potential, V _ = C V C + C = V 2
Then the energy stored in the capacitor,
U f = 1 2 ( 2 C ) ( V 2 ) 2 = 1 4 C V 2 ...(ii)
_ From eqns. (i) and (ii)
U f = U i 2
that means the total electrostatic energy of resulting system will decreases by a factor of 2.