Verified Solution • 2025–26 Session moderate

QNEET-2017-Ch-922: NEET 2017 Chemistry - Class 12 NEET-2017-Ch-922 Solution: In the electrochemical cell:…

In the electrochemical cell: Zn∣ZnSO4(0.01M)∣∣CuSO4(1.0M)∣CuZn|ZnSO_4(0.01M)||CuSO_4(1.0M)|Cu the emf of this Daniell cell is E1E_1. When the concentration of ZnSO4ZnSO_4 is changed to 1.0 M and that of CuSO4CuSO_4 changed to 0.01 M the emf changes to E2E_2. From the followings which one is the relationship between E1E_1 and E2E_2? (Given RT/F = 0.059) E1<E2E_1 < E_2 E1>E2E_1 > E_2 E2=0.1E1E_2 = 0.1E_1 E1=E2E_1 = E_2

Multiple Choice Options

  • A E 1 < E 2
  • B E 1 > E 2
  • C E 2 = 0 1 E 1
  • D E 1 = E 2

Step-by-Step Verified Solution

E cell = E o - 0.059 n log _ [ Z n 2 + ] [ C u 2 + ] E 1 = E o - 0.059 2 log _ 0.01 1 = E o - 0.059 2 ( _ 2 ) log _ 10 E 1 = E o + 0.059 E 2 = E o - 0.059 2 log _ 1 0.01 _ E 2 = E o - 0.059 2 log _ 100 _ E 2 = E o - 0.059 _ E 1 > E 2

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