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QNEET-2016-Ph-1174: NEET 2016 Physics - Class 11 NEET-2016-Ph-1174 Solution: A body of mass m is attached to the lower end of a spring whose …
A body of mass m is attached to the lower end of a spring whose upper end is fixed. The spring has negligible mass. When the mass m is slightly pulled down and released it oscillates with a time period of 3 s. When the mass m is increased by 1 kg the time period of oscillations becomes 5 s. The value of m in kg is 4/3 3/4 9/16 16/9
Multiple Choice Options
- A 4 3 _
- B 3 4 _
- C 9 16 _
- D 16 9 _
Step-by-Step Verified Solution
The time period of oscillation is given by
T = 2 � m / k
T 1 = 3 = 2 � m / k
T 2 = 5 = 2 � ( m + 1 k )
On dividing :
3 / 5 = m / ( m + 1 )
9 / 25 = m / ( m + 1 )
9 m + 9 = 25 m
16 m = 9 _ m = 9 / 16