Verified Solution • 2025–26 Session moderate

QNEET-2016-Ph-1173: NEET 2016 Physics - Class 12 NEET-2016-Ph-1173 Solution: If an electron in a hydrogen atom jumps from the 3rd orbit to…

If an electron in a hydrogen atom jumps from the 3rd orbit to the 2nd orbit it emits a photon of wavelength λ\lambda. When it jumps from the 4th orbit to the 3rd orbit the corresponding wavelength of the photon will be 1625λ\frac{16}{25}\lambda 916λ\frac{9}{16}\lambda 207λ\frac{20}{7}\lambda 2013λ\frac{20}{13}\lambda

Multiple Choice Options

  • A 1625λ{{16} \over {25}}\lambda 25 16 _ _
  • B 916λ{9 \over {16}}\lambda 16 9 _ _
  • C 207λ{{20} \over 7}\lambda 7 20 _ _
  • D 2013λ{{20} \over {13}}\lambda 13 20 _ _

Step-by-Step Verified Solution

When electron jumps from higher orbit to lower orbit then, wavelength of emitted photon is given by, 1 _ = R ( 1 n f 2 _ 1 n i 2 ) On jumping from 3 rd orbit to 2 nd orbit, 1 _ = R ( 1 2 2 _ 1 3 2 ) = 5 R 36 On jumping from 4 th orbit to 3 rd orbit, 1 _ _ = R ( 1 3 2 _ 1 4 2 ) = 7 R 144 _ _ ' = 144 7 _ 5 _ 36 = 20 _ 7

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