Verified Solution • 2025–26 Session moderate

QNEET-2016-Ph-1170: NEET 2016 Physics - Class 11 NEET-2016-Ph-1170 Solution: Two identical bodies are made of a material for which the heat…

Two identical bodies are made of a material for which the heat capacity increases with temperature. One of these is at 100∘C100^\circ C while the other one is at 0∘C0^\circ C. If the two bodies are brought into contact then assuming no heat loss the final common temperature is 50∘C50^\circ C more than 50∘C50^\circ C less than 50∘C50^\circ C but greater than 0∘C0^\circ C 0∘C0^\circ C

Multiple Choice Options

  • A 50 o C
  • B more than 50 o C
  • C less than 50 o C but greater than 0 o C
  • D 0 o C

Step-by-Step Verified Solution

If the final common temperature is T c , C c and C h average heat capacities of cold and hot bodies then as per principle of calorimetry, heat lost = heat gained C h (100�C � T c ) = C c _ T c Now T c = C h /(C h + C c ) _ 100�C = 100/[1 + (C c /C h )],     where C c /C h < 1 It is seen that 1 + C c /C h < 2 Hence, T c > (100/2)�C or T c > 50�C

Related Learning Resources & Exam Preparation

NEET PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring