Verified Solution • 2025–26 Session moderate

QNEET-2016-Ph-1160: NEET 2016 Physics - Class 11 NEET-2016-Ph-1160 Solution: Two rotating bodies A and B of masses m and 2m with moments of…

Two rotating bodies A and B of masses m and 2m with moments of inertia

I_A

and

I_B

(

I_B > I_A

) have equal kinetic energy of rotation. If

L_A

and

L_B

be their angular momenta respectively then

L_A = \frac{L_B}{2}

L_A = 2L_B

L_B > L_A

L_A > L_B

Multiple Choice Options

A ${L_A} = {{{L_B}} \over 2}$ L A _ = 2 L B _ _
B ${L_A} = 2{L_B}$ L A _ = 2 L B _
C ${L_B} > {L_A}$ L B _ > L A _
D ${L_A} > {L_B}$ L A _ > L B _

Step-by-Step Verified Solution

It is known that rotational kinetic energy is given as : E = I _ 2 2 = L 2 2 I Hence, L 2 _ I Further, E A = E B Also, L A 2 2 I A = L B 2 2 I B I B > I A L B > L A

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