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QNEET-2016-Ph-1152: NEET 2016 Physics - Class 12 NEET-2016-Ph-1152 Solution: An electron is moving in a circular path under the influence of …

An electron is moving in a circular path under the influence of a transverse magnetic field of

3.57 \times 10^{-2}\ \text{T}

. If the value of e/m is

1.76 \times 10^{11}\ \text{C kg}^{-1}

the frequency of revolution of the electron is 1 GHz 100 MHz 62.8 MHz 6.28 MHz

Step-by-Step Verified Solution

Frequency of revolution of charge in magnetic field is given as F = q B 2 � m = ( 1.76 _ 10 11 ) _ 3.57 _ 10 _ 2 2 _ 3.14 = 10 9 Hz = 1 GHz