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QNEET-2016-Ph-1151: NEET 2016 Physics - Class 11 NEET-2016-Ph-1151 Solution: A rectangular film of liquid is extended from (4 cm _ 2 cm) to…

A rectangular film of liquid is extended from (4 cm _ 2 cm) to (5 cm _ 4 cm). If the work done is 3×10−4 J3 \times 10^{-4}\ \text{J} the value of the surface tension of the liquid is 0.250 N m−10.250\ \text{N m}^{-1} 0.125 N m−10.125\ \text{N m}^{-1} 0.2 N m−10.2\ \text{N m}^{-1} 8.0 N m−18.0\ \text{N m}^{-1}

Multiple Choice Options

  • A 0.250 N m −- _ 1
  • B 0.125 N m −- _ 1
  • C 0.2 N m −- _ 1
  • D 8.0 N m −- _ 1

Step-by-Step Verified Solution

We have d = 2700 m, _ = 10 3 kg/m3, compressibility = 45.4 _ 10 _11 /pascal Now the pressure at bottom of ocean is p = _gd = 10 3 _ 10 _ 2700 = 27 _ 10 6 Pa Hence, fractional compression = 45.4 _ 10 _11 _ 27 _ 10 6 = 1.2 _ 10 _2 = 0.125 N m _ 1

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