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QNEET-2016-Ph-1083: NEET 2016 Physics - Class 11 NEET-2016-Ph-1083 Solution: A black body is at a temperature of 5760 K. The energy of…

A black body is at a temperature of 5760 K. The energy of radiation emitted by the body at wavelength 250 nm is U1U_1 at wavelength 500 nm is U2U_2 and that at 1000 nm is U3U_3. Wien's constant b=2.88×106 nm Kb = 2.88 \times 10^6\ \text{nm K}. Which of the following is correct? U1>U2U_1 > U_2 U2>U1U_2 > U_1 U1=0U_1 = 0 U3=0U_3 = 0

Multiple Choice Options

  • A U 1 > U 2
  • B U 2 > U 1
  • C U 1 = 0
  • D U 3 = 0

Step-by-Step Verified Solution

According to wein's displacement law, maximum amount of emitted radiation corresponding to _ m = b T _ m = 2.88 _ 10 6 n m K 5760 K = 500 n m From the graph U 1 < U 2 > U 3

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