Verified Solution • 2025–26 Session moderate

QNEET-2016-Ph-1069: NEET 2016 Physics - Class 11 NEET-2016-Ph-1069 Solution: A uniform circular disc of radius 50 cm at rest is free to turn …

A uniform circular disc of radius 50 cm at rest is free to turn about an axis which is perpendicular to its plane and passes through its centre. It is subjected to a torque which produces a constant angular acceleration of 2.0 rad s−22.0\ \text{rad s}^{-2}. Its net acceleration in m s−2\text{m s}^{-2} at the end of 2.0 s is approximately 6.0 3.0 8.0 7.0

Multiple Choice Options

  • A 6
  • B 3
  • C 8
  • D 7

Step-by-Step Verified Solution

Given, r = 50 cm = 0.5 m, _ = 2.0 rad s �2 , _ 0 = 0 At the end of 2 s, Tangential acceleration, at = r _ = 0.5 _ 2 = 1 m s �2 Radial acceleration, = a r = _ 2 r = ( _ 0 + _ t ) 2 r = (0 + 2 _ 2) 2 _ 0.5 = 8 m s �2 _ Net acceleration, a = a t 2 + a r 2 = 1 2 + 8 2 = 65 � 8 m s _ 2

Related Learning Resources & Exam Preparation