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QNEET-2016-Ph-1068: NEET 2016 Physics - Class 12 NEET-2016-Ph-1068 Solution: An electron of mass m and a photon have same energy E. The…

An electron of mass m and a photon have same energy E. The ratio of de-Broglie wavelengths associated with them is c(2mE)1/2c(2mE)^{1/2} 1c(E2m)1/2\frac{1}{c}(\frac{E}{2m})^{1/2} 1c(2mE)1/2\frac{1}{c}(\frac{2m}{E})^{1/2} (2mE)1/2(\frac{2m}{E})^{1/2}

Multiple Choice Options

  • A c(2mE)12c{\left( {2mE} \right)^{{1 \over 2}}} c ( 2 m E ) 2 1 _
  • B 1c(2mE)12{1 \over c}{\left( {{{2m} \over E}} \right)^{{1 \over 2}}} c 1 _ ( E 2 m _ ) 2 1 _
  • C 1c(E2m)12{1 \over c}{\left( {{E \over {2m}}} \right)^{{1 \over 2}}} c 1 _ ( 2 m E _ ) 2 1 _
  • D (E2m)12{\left( {{E \over {2m}}} \right)^{{1 \over 2}}} ( 2 m E _ ) 2 1 _

Step-by-Step Verified Solution

For electron De-Broglie wavelength, _ e = h 2 m E For photon of energy, E = h _ = h c _ p _ _ p = h c E _ _ e _ p = h 2 m E _ E h c = 1 c ( E 2 m ) 1 2

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