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QNEET-2016-Ph-1066: NEET 2016 Physics - Class 12 NEET-2016-Ph-1066 Solution: Consider the junction diode as ideal. The value of current…

Consider the junction diode as ideal. The value of current flowing through AB is 10−1 A10^{-1}\ \text{A} 10−3 A10^{-3}\ \text{A} 0 A 10−2 A10^{-2}\ \text{A}

Multiple Choice Options

  • A 10 −- _ 1 A
  • B 10 −- _ 3 A
  • C 12A
  • D 10 −- _ 2 A

Step-by-Step Verified Solution

Here, the p-n junction diode is forward biased, hence it offers zero resistance. So I AB = 4 _ ( _ 6 ) 1 _ 10 3 = 10 -2 A

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