Verified Solution • 2025–26 Session moderate

QNEET-2016-Ph-1065: NEET 2016 Physics - Class 12 NEET-2016-Ph-1065 Solution: Two identical charged spheres suspended from a common point by…

Two identical charged spheres suspended from a common point by two massless strings of lengths l are initially at a distance d (d << l) apart because of their mutual repulsion. The charges begin to leak from both the spheres at a constant rate. As a result the spheres approach each other with a velocity v. Then v varies as a function of the distance x between the spheres as v∝x−1/2v \propto x^{-1/2} v∝x−1v \propto x^{-1} v∝x1/2v \propto x^{1/2} v∝xv \propto x

Multiple Choice Options

  • A v ∝\propto _ x −- _ 1/2
  • B v ∝\propto _ x −- _ 1
  • C v ∝\propto _ x 1/2
  • D v ∝\propto _ x

Step-by-Step Verified Solution

From figure tan _ _ = F e m g _ _ k q 2 x 2 m g = x 2 _ _ x 3 _ q 2    ...(i) _ x 3 / 2 _ q Differentiating eq. (1) w.r.t. time 3 x 2 d x d t _ 2 q d q d t but d q d t is constant so x 2 (v) _ q Replace q from eq. (2) x 2 (v) _ x 3/2 _ v _ x �1/2

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