Verified Solution • 2025–26 Session moderate

QNEET-2016-Ph-1059: NEET 2016 Physics - Class 11 NEET-2016-Ph-1059 Solution: A car is negotiating a curved road of radius R. The road is…

A car is negotiating a curved road of radius R. The road is banked at an angle θ\theta. The coefficient of friction between the tyres of the car and the road is μs\mu_s. The maximum safe velocity on this road is Rgμs+tan⁡θ1−μstan⁡θ\sqrt{Rg\frac{\mu_s+\tan\theta}{1-\mu_s\tan\theta}} R2gμs+tan⁡θ1−μstan⁡θ\sqrt{R^2g\frac{\mu_s+\tan\theta}{1-\mu_s\tan\theta}} gR2μs+tan⁡θ1−μstan⁡θ\sqrt{gR^2\frac{\mu_s+\tan\theta}{1-\mu_s\tan\theta}} gRμs+tan⁡θ1−μstan⁡θ\sqrt{gR\frac{\mu_s+\tan\theta}{1-\mu_s\tan\theta}}

Multiple Choice Options

  • A gRμs+tan⁡θ1−μstan⁡θ\sqrt {{g \over R}{{{\mu _s} + \tan \theta } \over {1 - {\mu _s}\tan \theta }}} R g _ 1 _ _ s _ tan _ _ s _ + tan _ _ _
  • B gR2μs+tan⁡θ1−μstan⁡θ\sqrt {{g \over {{R^2}}}{{{\mu _s} + \tan \theta } \over {1 - {\mu _s}\tan \theta }}} R 2 g _ 1 _ _ s _ tan _ _ s _ + tan _ _ _
  • C gR2μs+tan⁡θ1−μstan⁡θ\sqrt {g{R^2}{{{\mu _s} + \tan \theta } \over {1 - {\mu _s}\tan \theta }}} g R 2 1 _ _ s _ tan _ _ s _ + tan _ _ _
  • D gRμs+tan⁡θ1−μstan⁡θ\sqrt {gR{{{\mu _s} + \tan \theta } \over {1 - {\mu _s}\tan \theta }}} g R 1 _ _ s _ tan _ _ s _ + tan _ _ _

Step-by-Step Verified Solution

On a banked road, V max 2 R g = ( _ s + tan _ _ 1 _ _ s tan _ _ ) Maximum safe velocity of a car on the banked road V max = R g [ _ s + tan _ _ 1 _ _ s tan _ _ ]

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