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QNEET-2016-Ph-1058: NEET 2016 Physics - Class 12 NEET-2016-Ph-1058 Solution: When an \( \)-particle of mass m moving with velocity v…

When an α\alpha-particle of mass m moving with velocity v bombards on a heavy nucleus of charge Ze its distance of closest approach from the nucleus depends on m as 1m2\frac{1}{m^2} 1m\frac{1}{m} m 1m\frac{1}{\sqrt{m}}

Multiple Choice Options

  • A 1m2{1 \over {{m^2}}} m 2 1 _
  • B m
  • C 1m{1 \over m} m 1 _
  • D 1m{1 \over {\sqrt m }} m _ 1 _

Step-by-Step Verified Solution

At closest distance of approach, the kinetic energy of the particle will convert completely into electrostatic potential energy. Kinetic energy = 1 2 m v 2 Potential energy = K Q q r _ 1 2 m v 2 = K Q q r _ r _ 1 m

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