Verified Solution • 2025–26 Session moderate

QNEET-2016-Ph-1057: NEET 2016 Physics - Class 11 NEET-2016-Ph-1057 Solution: A uniform rope of length L and mass \(m_1\) hangs vertically…

A uniform rope of length L and mass m1m_1 hangs vertically from a rigid support. A block of mass m2m_2 is attached to the free end of the rope. A transverse pulse of wavelength λ1\lambda_1 is produced at the lower end of the rope. The wavelength of the pulse when it reaches the top of the rope is λ2\lambda_2. The ratio λ2/λ1\lambda_2/\lambda_1 is m1m2\sqrt{\frac{m_1}{m_2}} m1+m2m1\sqrt{\frac{m_1+m_2}{m_1}} m2m1\sqrt{\frac{m_2}{m_1}} m1+m2m2\sqrt{\frac{m_1+m_2}{m_2}}

Multiple Choice Options

  • A m2m1\sqrt {{{{m_2}} \over {{m_1}}}} m 1 _ m 2 _ _ _
  • B m1+m2m1\sqrt {{{{m_1} + {m_2}} \over {{m_1}}}} m 1 _ m 1 _ + m 2 _ _ _
  • C m1m2\sqrt {{{{m_1}} \over {{m_2}}}} m 2 _ m 1 _ _ _
  • D m1+m2m2\sqrt {{{{m_1} + {m_2}} \over {{m_2}}}} m 2 _ m 1 _ + m 2 _ _ _

Step-by-Step Verified Solution

Wavelength of pulse at the lower end _ 1 _ v e l o c i t y ( v 1 ) = T 1 _ Similarly, _ 1 _ v 2 = T 2 _ _ _ 2 _ 1 = T 2 T 1 = ( m 1 + m 2 ) g m 2 g = m 1 + m 2 m 2

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