QNEET-2016-Ph-1056: NEET 2016 Physics - Class 12 NEET-2016-Ph-1056 Solution: A capacitor of \(2 F\) is charged as shown in the diagram. When …

Initially, the energy stored in 2 _ F capacitor is U i = 1 2 C V 2 = 1 2 ( 2 _ 10 _ 6 ) V 2 = V 2 _ 10 _ 6 J Initially, the charge stored in 2 _ F capacitor is Q i = CV = (2 _ 10 �6 )V = 2V _ 10 �6 coulomb. When switch S is turned to position 2, the charge flows and both the capacitors share charges till a common potential V C is reached. V C = t o t a l charge t o t a l c a p a c i t a n c e = 2 V _ 10 _ 6 ( 2 + 8 ) _ 10 _ 6 = V 5 v o l t Finally, the energy stored in both the capacitors U f = 1 2 [ ( 2 + 8 ) _ 10 _ 6 ] ( V 5 ) = V 2 5 _ 10 _ 6 J % loss of energy, _ U = U i _ U f U i _ 100 % = ( V 2 _ V 2 / 5 ) _ 10 _ 6 V 2 _ 10 _ 6 _ 100 % = 80 %