Verified Solution • 2025–26 Session moderate

QNEET-2016-Ph-1054: NEET 2016 Physics - Class 12 NEET-2016-Ph-1054 Solution: Given the value of Rydberg constant is \(10^7\ {m}^{-1}\) the…

Given the value of Rydberg constant is 107 m−110^7\ \text{m}^{-1} the wave number of the last line of the Balmer series in hydrogen spectrum will be 0.25×107 m−10.25 \times 10^7\ \text{m}^{-1} 2.5×107 m−12.5 \times 10^7\ \text{m}^{-1} 0.025×104 m−10.025 \times 10^4\ \text{m}^{-1} 0.5×107 m−10.5 \times 10^7\ \text{m}^{-1}

Multiple Choice Options

  • A 0.25 ×\times _ 10 7 m −- _ 1
  • B 2.5 ×\times _ 10 7 m −- _ 1
  • C 0.025 ×\times _ 10 4 m −- _ 1
  • D 0.5 ×\times _ 10 7 m −- _ 1

Step-by-Step Verified Solution

The wave number of the last line of the Balmer series in hydrogen spectrum is given by 1 _ = R ( 1 2 2 _ 1 � 2 ) = R 4 = 10 7 4 = 0.25 _ 10 7 m _ 1

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