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QNEET-2016-Ph-1053: NEET 2016 Physics - Class 12 NEET-2016-Ph-1053 Solution: An inductor 20 mH a capacitor \(50 F\) and a resistor \(40 \)…
An inductor 20 mH a capacitor and a resistor are connected in series across a source of emf V = 10 sin 340t. The power loss in A.C. circuit is 0.76 W 0.89 W 0.51 W 0.67 W
Multiple Choice Options
- A 0.76 W
- B 0.89 W
- C 0.51 W
- D 0.67 W
Step-by-Step Verified Solution
X L = _ L = 340 _ 20 _ 10 -3 = 6.8 �
X C = 1 340 _ 50 _ 10 _ 6 = 58.82 �
Average power in impedance
Z = R 2 + ( X C _ X L ) 2
= 40 2 + ( 58.82 _ 6.8 ) 2 = 65.62 �
Power loss in A.C. circuit,
= V rms I rms cos _
= 1 2 V 0 I 0 cos _
= 1 2 _ 10 _ 10 65.62 _ 40 65.62
= 0.46 W