Verified Solution • 2025–26 Session moderate

QNEET-2016-Ph-1052: NEET 2016 Physics - Class 12 NEET-2016-Ph-1052 Solution: In a diffraction pattern due to a single slit of width a the…

In a diffraction pattern due to a single slit of width a the first minimum is observed at an angle 30∘30^\circ when light of wavelength 5000 A˚\text{\AA} is incident on the slit. The first secondary maximum is observed at an angle of sin⁡−1(12)\sin^{-1}(\frac{1}{2}) sin⁡−1(34)\sin^{-1}(\frac{3}{4}) sin⁡−1(14)\sin^{-1}(\frac{1}{4}) sin⁡−1(23)\sin^{-1}(\frac{2}{3})

Multiple Choice Options

  • A sin −- _ 1 (12)\left( {{1 \over 2}} \right) ( 2 1 _ )
  • B sin⁡−1(34){\sin ^{ - 1}}\left( {{3 \over 4}} \right) sin _ 1 ( 4 3 _ )
  • C sin⁡−1(14){\sin ^{ - 1}}\left( {{1 \over 4}} \right) sin _ 1 ( 4 1 _ )
  • D sin⁡−1(23){\sin ^{ - 1}}\left( {{2 \over 3}} \right) sin _ 1 ( 3 2 _ )

Step-by-Step Verified Solution

For the first minima, the path difference between extreme waves sin _ = _ a _ 1 2 = _ a _ a = 2 _ For first secondary maximum, the path difference between extreme waves sin _ _ _ = 3 _ 2 a = 3 2 ( 1 2 ) _ _ _ = sin _ 1 ( 3 4 )

Related Learning Resources & Exam Preparation

NEET PYQ Question Bank
Browse year-wise authentic previous years' questions with solutions
Authentic CBT Mock Tests
Simulate official exam environment with live timer and percentile scoring