Verified Solution • 2025–26 Session moderate

QNEET-2016-Ch-1121: NEET 2016 Chemistry - Class 11 NEET-2016-Ch-1121 Solution: The solubility of AgCl(s) with solubility product \(1.6…

The solubility of AgCl(s) with solubility product 1.6×10−101.6 \times 10^{-10} in 0.1 M NaCl solution would be 1.26×10−5 M1.26 \times 10^{-5}\ \text{M} 1.6×10−9 M1.6 \times 10^{-9}\ \text{M} 1.6×10−11 M1.6 \times 10^{-11}\ \text{M} zero

Multiple Choice Options

  • A 1.26 ×\times _ 10 −- _ 5 M
  • B 1.6 ×\times _ 10 −- _ 9 M
  • C 1.6 ×\times _ 10 −- _ 11 M
  • D zero

Step-by-Step Verified Solution

AgCl _ Ag + + Cl �    s           s     s + 0.1 Concentration of Cl � is (s + 0.1) mol L �1 because s mol L �1 from ionization of AgCl and 0.1 mol L �1 from ionization of 0.1 M NaCl. Now, K sp = [Ag + ][Cl � ] _ 1.6 _ 10 �10 = s (s + 0.1) _ 1.6 _ 10 �10 = s (0.1) { _ s << 0.1} _ s = 1.6 _ 10 �9 M

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