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QNEET-2016-Ch-1106: NEET 2016 Chemistry - Class 11 NEET-2016-Ch-1106 Solution: The percentage of pyridine (\(C_5H_5N\)) that forms pyridinium…

The percentage of pyridine (C5H5NC_5H_5N) that forms pyridinium ion (C5H5N+HC_5H_5N^+H) in a 0.10 M aqueous pyridine solution (KbK_b for C5H5N=1.7×10−9C_5H_5N = 1.7 \times 10^{-9}) is 0.0060% 0.013% 0.77% 1.6%

Multiple Choice Options

  • A 0.01%
  • B 0.01%
  • C 0.77%
  • D 1.60%

Step-by-Step Verified Solution

C 5 H 5 N + H 2 O _ C 5 H 5 N + H + OH � So, the amount of pyridine that forms pyridinium ion is _ . Now, _ = K b c o n c . o f p y r i d i n e = 1.7 _ 10 9 0.10 = 1.30 _ 10 -4 So, percentage of pyridine that forms pyridinium ion = 1.30 _ 10 �4 _ 100 = 1.30 _ 10 �2 = 0.013%

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