Verified Solution • 2025–26 Session moderate

QNEET-2016-Ch-1044: NEET 2016 Chemistry - Class 11 NEET-2016-Ch-1044 Solution: Consider the molecules \(CH_4 NH_3\) and \(H_2O\). Which of the …

Consider the molecules CH4NH3CH_4 NH_3 and H2OH_2O. Which of the given statements is false? The H-O-H bond angle in H2OH_2O is smaller than the H-N-H bond angle in NH3NH_3. The H-C-H bond angle in CH4CH_4 is larger than the H-N-H bond angle in NH3NH_3. The H-C-H bond angle in CH4CH_4 the H-N-H bond angle in NH3NH_3 and the H-O-H bond angle in H2OH_2O are all greater than 90∘90^\circ. The H-O-H bond angle in H2OH_2O is larger than the H-C-H bond angle in CH4CH_4.

Multiple Choice Options

  • A The H −- _ O −- _ H bond angle in H 2 O is smaller than the H −- _ N −- _ H bond angle in NH 3 .
  • B The H −- _ C −- _ H bond angle in CH 4 is larger than the H −- _ N −- _ H bond angle in NH 3 .
  • C The H −- _ C −- _ H bond angle in CH 4 , the H −- _ N −- _ H bond angle in NH 3 , and the H −- _ O −- _ H bond angle in H 2 O are all greater than 90 o .
  • D The H −- _ O −- _ H bond angle in H 2 O is larger than the H −- _ C −- _ H bond angle in CH 4 .

Step-by-Step Verified Solution

In CH 4 , there is no lone pair of electrons so it is perfectly tetrahedral in shape and has H-C-H bond angle of 109�28_ but in NH 3 there is one lone pair which due to more repulsion with bond pairs of electrons pushes them more closer thus bond angle decreases to 107�. In H 2 O, there are two lone pair of electrons which suppress the bond angle more to 104.5�.

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